Question past exam Quiz 2 - 2019

Re: Question past exam Quiz 2 - 2019

par Kalpani Anuradha Welivita,
Number of replies: 0
I think this is because we can write P(T1=t1, ... Tn=tn | W1=w1, ... Wn = wn) in the following way:

P(T1=t1, ... Tn=tn, W1=w1, ... Wn = wn) / P(W1=w1, ... Wn = wn)

For a fixed word sequence, P(W1=w1, ... Wn = wn) will be fixed. Thus, maximizing P(T1=t1, ... Tn=tn | W1=w1, ... Wn = wn) will be the same as maximizing P(T1=t1, ... Tn=tn,W1=w1, ... Wn = wn).