Question about an exampel for Cut-off Edit Distance

Re: Question about an exampel for Cut-off Edit Distance

by Jean-Cédric Chappelier -
Number of replies: 0

You're right: in general there is the min(n, max(1, ...)), but here I foccused only the main part : m-\theta, then realize that it leads to the same result here since the min (of D) is on the diagonal: min (1, 0, 1) = min (0, 1).
Sorry for confusion if that specific case was unclear.