2021 Exam solutions by Giorgio Mannarini - Wednesday, 5 January 2022, 18:57 Number of replies: 3 Hi! Is it possible to have the solutions for the 2021 exam? It would be great for our preparation :)Thank you,Best,Giorgio Permalink Reply In reply to Giorgio Mannarini Re: 2021 Exam solutions by Jean-Cédric Chappelier - Tuesday, 11 January 2022, 16:00 Sure! Here it comes. exam20-inlp-solution.pdf Permalink Show parent Reply In reply to Jean-Cédric Chappelier Re: 2021 Exam solutions by Johanna Sofia Louise Frost - Friday, 21 January 2022, 09:15 Thank you for the exam and solutions. I have a short question about one answer. Why is the a root sign in question 7.2? It seems to me that it simply should be D * "t" = 1 in the nominator, and |D| * |"t"| = |D| in the denominator. Permalink Show parent Reply In reply to Johanna Sofia Louise Frost Re: 2021 Exam solutions by Jean-Cédric Chappelier - Monday, 24 January 2022, 10:18 don't confuse (length of ) and (Euclidean norm) Permalink Show parent Reply
In reply to Giorgio Mannarini Re: 2021 Exam solutions by Jean-Cédric Chappelier - Tuesday, 11 January 2022, 16:00 Sure! Here it comes. exam20-inlp-solution.pdf Permalink Show parent Reply In reply to Jean-Cédric Chappelier Re: 2021 Exam solutions by Johanna Sofia Louise Frost - Friday, 21 January 2022, 09:15 Thank you for the exam and solutions. I have a short question about one answer. Why is the a root sign in question 7.2? It seems to me that it simply should be D * "t" = 1 in the nominator, and |D| * |"t"| = |D| in the denominator. Permalink Show parent Reply In reply to Johanna Sofia Louise Frost Re: 2021 Exam solutions by Jean-Cédric Chappelier - Monday, 24 January 2022, 10:18 don't confuse (length of ) and (Euclidean norm) Permalink Show parent Reply
In reply to Jean-Cédric Chappelier Re: 2021 Exam solutions by Johanna Sofia Louise Frost - Friday, 21 January 2022, 09:15 Thank you for the exam and solutions. I have a short question about one answer. Why is the a root sign in question 7.2? It seems to me that it simply should be D * "t" = 1 in the nominator, and |D| * |"t"| = |D| in the denominator. Permalink Show parent Reply In reply to Johanna Sofia Louise Frost Re: 2021 Exam solutions by Jean-Cédric Chappelier - Monday, 24 January 2022, 10:18 don't confuse (length of ) and (Euclidean norm) Permalink Show parent Reply
In reply to Johanna Sofia Louise Frost Re: 2021 Exam solutions by Jean-Cédric Chappelier - Monday, 24 January 2022, 10:18 don't confuse (length of ) and (Euclidean norm) Permalink Show parent Reply